A simple coding system, using cryptograms, is designed as below. Three concentric wheels each having all the alphabets and the number 0 to 9 are written around the rims of the wheels.
Questions
1. Suppose that a cryptogram system is made by rotating the inner wheel 2 alphabets to the right and
rotating the outer wheel 2 alphabets to the left. Starting with the inner wheel, what would APPLE
be coded as?
(1) BRRC7 (2) 8RNJC (3) 8CCNR (4) 8RNNC
2. How many cryptogram system can be totally made from this device? (Starting inner wheel)
(1) 2315 (2) 1295 (3) 676 (4) Indeterminate
3. Assume that both the inner and outer wheels have been rotated one step, but you don’t know
whether left or right. What would the rotations be if HOCJ9 has to decode to a proper English
word? (Starting inner wheel)
(1) Inner right, Outer right (2) Inner left, Outer left
(3) Inner right, Outer left (4) Inner left, Outer right
Answers
1. (4) Right turns: Actual letter – 2, 2 left turns : Actual letter + 2
A (inner) : 8; P (outer) : R ; P (inner): N; L (outer) : N; E (inner) : C
∴ APPLE would be coded as 8RNNC.
2. (2) Total alphabets + number on a wheel = 26 + 10 = 36 per wheel
Total combinations = (36 x 36) – 1 = 1295 (one is where all wheels are aligned)
3. (3) 4 combinations possible :
Inner L, Outer L, Inner R, Outer R, Inner L, Outer R and Inner R, Outer L.
Translate HOCJ9 back in each of the four above, and the only one which would reproduce an
English an English word (INDIA) is inner R, outer L.
Questions
1. Suppose that a cryptogram system is made by rotating the inner wheel 2 alphabets to the right and
rotating the outer wheel 2 alphabets to the left. Starting with the inner wheel, what would APPLE
be coded as?
(1) BRRC7 (2) 8RNJC (3) 8CCNR (4) 8RNNC
2. How many cryptogram system can be totally made from this device? (Starting inner wheel)
(1) 2315 (2) 1295 (3) 676 (4) Indeterminate
3. Assume that both the inner and outer wheels have been rotated one step, but you don’t know
whether left or right. What would the rotations be if HOCJ9 has to decode to a proper English
word? (Starting inner wheel)
(1) Inner right, Outer right (2) Inner left, Outer left
(3) Inner right, Outer left (4) Inner left, Outer right
Answers
1. (4) Right turns: Actual letter – 2, 2 left turns : Actual letter + 2
A (inner) : 8; P (outer) : R ; P (inner): N; L (outer) : N; E (inner) : C
∴ APPLE would be coded as 8RNNC.
2. (2) Total alphabets + number on a wheel = 26 + 10 = 36 per wheel
Total combinations = (36 x 36) – 1 = 1295 (one is where all wheels are aligned)
3. (3) 4 combinations possible :
Inner L, Outer L, Inner R, Outer R, Inner L, Outer R and Inner R, Outer L.
Translate HOCJ9 back in each of the four above, and the only one which would reproduce an
English an English word (INDIA) is inner R, outer L.
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